Cd Si volume relaxation

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Task

Relaxation of the internal coordinates, volume and cell shape in cd Si.

Input

POSCAR

cubic diamond
   5.5
 0.0    0.5     0.5
 0.5    0.0     0.5
 0.5    0.5     0.0
  2
Direct
 -0.125 -0.125 -0.125
  0.125  0.125  0.125

INCAR

System = diamond Si
ISMEAR = 0; SIGMA = 0.1;
ENMAX  =  240
IBRION = 2; ISIF=3 ; NSW=15
EDIFF  = 0.1E-04
EDIFFG = -0.01

• IBRION=2 conjugate-gradient algorithm.
• ISIF=3 change of internal parameter, shape and volume simultaneously.

KPOINTS

k-points
 0
Monkhorst Pack
 11 11 11
 0  0  0

Calculation

• To determine the equilibrium volume we can:
  • Fit the energz over a certain volume range to an equation of state (see cd_Si.
  • Alternatively we relax the structure with VASP "on the fly" (IBRION=2 and ISIF=3)

• From equation of states we determine lattice parameter of $a=5.4687$ $\mathrm {\AA}$ (volume scan plus Murnaghan EOS using ENMAX=400).

• From relaxations using IBRION=2 and ISIF=3 we get $a=5.4684$ $\mathrm {\AA}$.

• Difference can be due to pulay stress (especially when the relaxation starts far away from equilibrium):

-------------------------------------------------------------------------------------
Total       0.00155     0.00155     0.00155    -0.00000     -0.00000      0.00000
in kB       0.06056     0.06056     0.06056    -0.00000     -0.00000      0.00000
external pressure =        0.06 kB  Pullay stress =          0.00 kB
   
   
VOLUME and BASIS-vectors are now :
-----------------------------------------------------------------------------
 energy-cutoff :      400.00
 volume of cell :      40.88
     direct lattice vectors                 reciprocal lattice vectors
    0.000000000  2.734185321  2.734185321    -0.182869828  0.182869828  0.182869828
    2.734185321  0.000000000  2.734185321     0.182869828 -0.182869828  0.182869828
    2.734185321  2.734185321  0.000000000     0.182869828  0.182869828 -0.182869828

Download

diamondSivolrel.tgz

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